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tpog
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« on: June 06, 2009, 08:34:24 PM » |
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Tell me the example of a natural number (0,1,2,3,etc.) that when we take off the first digit we'll get a higher number as a result.
In example for 23, we'll take off the first digit, the result is 3. But unfortunatelly 3 is not higher than 23. So find another number(s) that will be the answer.
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Kelly2
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« Reply #1 on: June 06, 2009, 08:44:01 PM » |
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I don't understand the cause of making a new thread, you didn't ask a question nor post a relevant subject.
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Warlock
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« Reply #2 on: June 06, 2009, 08:59:40 PM » |
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Is there any?
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tpog
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« Reply #3 on: June 06, 2009, 09:00:49 PM » |
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I don't understand the cause of making a new thread, you didn't ask a question nor post a relevant subject.
There are a lot of things I don't understand, as well. |
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Twitter@
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« Reply #4 on: June 06, 2009, 09:35:28 PM » |
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32465 ?
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When you believe in what you're doing and use your imagination and initiative, you can make a difference.
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Warlock
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« Reply #5 on: June 06, 2009, 09:43:31 PM » |
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2465<32465
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general vegitable
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« Reply #6 on: June 06, 2009, 11:33:32 PM » |
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how about -42
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website down until further notice
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inp o҉rtb
The Gangsta
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experimental theologian
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« Reply #7 on: June 06, 2009, 11:46:39 PM » |
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how about -42 -42 is not a natural number. |
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uh_Iforgot
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« Reply #8 on: June 06, 2009, 11:52:06 PM » |
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how about -42
Natural numbers = non-negative, non decimal numbers.  Edit: Awww, inp o҉rtb got there first. |
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« Last Edit: June 06, 2009, 11:58:35 PM by uh_Iforgot »
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thefluffball
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« Reply #9 on: June 07, 2009, 12:07:10 AM » |
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0.2 OR  ?  |
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« Last Edit: June 07, 2009, 12:21:04 AM by thefluffball »
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uh_Iforgot
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« Reply #10 on: June 07, 2009, 12:41:05 AM » |
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0.2 OR ? Not natural numbers... |
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thefluffball
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« Reply #11 on: June 07, 2009, 01:25:19 AM » |
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Not natural numbers... Woops, sorry, didn't read properly. Surely this is impossible as a n-1 digit number will always be smaller than a n digit number. There's got to be some trick... |
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Confuser
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« Reply #12 on: June 07, 2009, 01:44:37 AM » |
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hmm what about 102? Take off the 1 and you are left with 02 which is bigger than 1  |
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thefluffball
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« Reply #13 on: June 07, 2009, 01:54:59 AM » |
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hmm what about 102? Take off the 1 and you are left with 02 which is bigger than 1 Does that really count?  |
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inp o҉rtb
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experimental theologian
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« Reply #14 on: June 07, 2009, 02:15:53 AM » |
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how about -42 Natural numbers = non-negative, non decimal numbers. saywhat?... natural numbers could be represented in any base as long as they're non-negative integers; you could have a hexadecimal natural number if you want. |
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manicgames
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« Reply #15 on: June 07, 2009, 02:22:45 AM » |
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I don't understand the cause of making a new thread, you didn't ask a question nor post a relevant subject.
So what? Nobody is forcing you to visit it. |
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Piotr GRD
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« Reply #16 on: June 07, 2009, 02:48:29 AM » |
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Hehe, thank you, tpog. So - anybody?  |
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uh_Iforgot
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« Reply #17 on: June 07, 2009, 03:11:56 AM » |
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how about -42 Natural numbers = non-negative, non decimal numbers. saywhat?... natural numbers could be represented in any base as long as they're non-negative integers; you could have a hexadecimal natural number if you want. So 0.1 is a natural number? |
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inp o҉rtb
The Gangsta
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experimental theologian
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« Reply #18 on: June 07, 2009, 03:29:51 AM » |
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how about -42 Natural numbers = non-negative, non decimal numbers. saywhat?... natural numbers could be represented in any base as long as they're non-negative integers; you could have a hexadecimal natural number if you want. So 0.1 is a natural number? You tell me: is 0.1 a non-negative integer?
Well let's see... any natural number could be expressed as N = Σn(bi·xi), where b is the [positive integer] base, xi is a positive integer, i varies from 0 to n, and n is 1 less than the number of digits in the particular base. For example, 123 = 100·3+101·2+102·1 Suppose we have another natural number M = Σn-1(bi·xi) and n > 0 (that is, Piotr GRD's problem setup). Firstly, we notice that N-M = bi·xn Recall that xn is the most significant digit of N, which M lacks. If M > N, then N-M < 0
bi·xn < 0 If b, i, and xn are non-negative according to the preconditions, we've hit a stumbling block |
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M0ZZA
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« Reply #19 on: June 07, 2009, 03:32:58 AM » |
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o.O
You lost me with Σn(bi·xi)
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